Avogadro's
Law proposed by Amedeo Avogadro
States that under equal conditions of temperature and
pressure, equal volumes of gases contain an equal number
of molecules.
This hypothesis was not acknowledged in Avogadro's
lifetime and it wasn't until Stanislao Cannizzaro, in
1860, demonstrated that it was the solution to the
problem of atomic and molecular weights that Avogadro's
Law became widely accepted. The number of particles in
one mole of a substance was named Avogadro's number in
his honour, and is numerically equal to 6.02252 x 10 23
from-http://www.chemsoc.org/timeline/pages/1811.html
Avogadro’s law, which is
derived from this basic idea, says that the volume of a
gas maintained at constant temperature and pressure is
directly proportional to the number of moles of the gas,
or
V
= constant x n (where n is the number of
moles of the gas)
which can be rearranged thus:

P = the gas absolute pressure, in atm
n = number of moles, in mol
V = the volume, in L
T = the gas absolute temperature, in K
R = the universal gas law constant of 0.0821 L·atm/(mol·K)
At
STP (1 atm, 273K), the volume of 1 mole of gas is
calculated to be 22.4L.
|
V= |
nRT |
= |
(1 mol)(0.0821)(273K) |
= 22.4L at STP |
| P |
1 atm |
Questions
Highlight ot reveal Answers
| Determine
the volume of 3.0 moles of He at STP.
|
3.0 moles of He x |
22.4L |
= 67.2L of
He |
| 1
mole |
| Determine
the volume of 0.5 moles of N2 at STP.
|
0.5 moles of
N2 x |
22.4L |
=11.2L
of N2 |
| 1
mole |
| Determine
the volume of 10. moles of CO2 at STP.
|
10. moles of
CO2 x |
22.4L |
=224L
of CO2 |
| 1
mole |
| Determine
the volume of 0.1 moles of Ne at STP.
|
0.1 moles of
Ne x |
22.4L |
=2.24L
of Ne |
| 1
mole |
|