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Here are the Rules from the other Page STEP1= SET UP the ICE Box STEP 2- Find the moles, This is where you have to problem solve. STEP 3- Find X, find the moles of everything STEP 4- Answer the questions, convert moles to mass The question- You have 20.0 g of elemental
sulfur, S, and 160.0 grams of O S
STEP1= SET UP the ICE Box below the balanced reaction. (I-Initial C-Change E-End). Using the coefficients, (the #'s in front of each compound) to determine the relative change. If there is a 2 in front, use 2X, if there is a 3 use 3X. Also reactants decrease in their amounts (-X), products will increase (+X).
Step 2- Moles are the only thing allowed in the ice box. Find the moles of each compound and insert that value in its I box.
Step 3- Find X, one of the reactants is limiting, which means it runs out. You end up with 2 possible scenarios for this reaction. if S runs out ==> 0.623 mol -X =O ; X is therefore 0.623 mol if O Which ever reactant gives you the lower value for X is the limiting reactant and this X value is applied as X in your ICE BOX. (If you applied the incorrect, larger X value, will get a negative amount at the end, so go back and change it.) Now solve for everything (add or subtract down each column).
Step 4- Answer the questions, you have them moles of everything. Convert to grams. What mass of SO
How much reactant is left over?
Level 2- The equation now has coefficients. If you are provided 200.g of sodium and 250. grams of iron(III) oxide, which substance is the limiting reactant? How many grams of Iron are produced? How much reactant is in excess?
6Na + Fe
STEP1= SET UP the ICE Box below the balanced reaction. (I-Initial C-Change E-End). Using the coefficients, (the #'s in front of each compound) to determine the relative change. If there is a 2 in front, use 2X, if there is a 3 use 3X. Also reactants decrease in their amounts (-X), products will increase (+X).
Step 2- Moles are the only thing allowed in the ice box. Find the moles of each compound and insert that value in its I box.
Step 3- Find X, one of the reactants is limiting, which means it runs out. You end up with 2 possible scenarios for this reaction. if Na runs out ==> 8.70 mol -6X =O ; X is therefore 1.45 mol if
Fe Which ever reactant gives you the lower value for X is the limiting reactant and this X value is applied as X in your ICE BOX. Na is therefore limiting. (If you applied the incorrect, larger X value, will get a negative amount at the end, so go back and change it.) Now solve for everything (add or subtract down each column).
Step 4- Answer the questions, you have them moles of everything. Convert to grams. How many grams of Iron are produced?
How much reactant is in excess?
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