In a titration, 50.0 milliliters
of 0.026 M HCl(aq) is neutralized by 38.5 milliliters of
KOH(aq).
62 In the space in your answer booklet, show a numerical
setup for calculating the molarity of the KOH(aq). [1]
Answer==> (0.026M)(50.0mL)=
Mb x (38.5mL) |
63 Complete the equation in your answer booklet for the
neutralization by writing the formula of the missing
product. [1]
on to
Questions 64-65 |