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Oxidation number is the
apparent charge of an atom in a compound.
Rules for assigning oxidation numbers.
Follow my order when you assign the
numbers and you never can go wrong.
1. Free elements are assigned an oxidation state of
zero.
ex. Fe, Ag, Br2
2. The Group 1 metals (Li, Na, K, Rb, and Cs) in
compounds are always assigned an oxidation state of
+1.
ex NaCl (Na +1, Cl -1)
3. The Group 2 metals (Be, Mg, Ca, Sr, Ba, and
Ra) and also Zn and Cd in compounds are always assigned
an oxidation state of +2.
4.Fluorine in compounds is always assigned an
oxidation state of -1. (The most electronegative
element.)
5. Hydrogen in compounds is assigned an
oxidation state of +1.
Exceptions Metal hydrides (you
already assigned group 1, so H must be -1)
NaH (Na +1, H-1)
6. Oxygen in compounds is assigned an oxidation state
of -2.
Exceptions Peroxides (you
already assigned hydrogen +1, so O must be -1)
H2O2 (H
+1, O-1)
With Fluorine (you already assigned
fluorine -1, so O must be +2)
OF2 ( O+2, F-1)
7. The sum of the oxidation states of all
that atoms in a species must be equal to the net charge on
the species.
SO42-
Since each O is -2 and the ox. numbers
add to 2-
S + 4(-2)=-2
S is +6
8. If all else fails, halogen in compounds
is assigned an oxidation state of -1.
More examples
Past Regents Questions
involving Oxidation Numbers
Jan 2007-45
What is the oxidation number of chromium in the chromate
ion, CrO42–?
(1) +6 (3) +3
(2) +2 (4) +8
Jan 2006-21 What is the oxidation number assigned to
manganese in KMnO4?
(1) +7 (3) +3
(2) +2 (4) +4
Jan 2003-4 In which compound does chlorine have the
highest oxidation number?
(1) NaClO
(3) NaClO3
(2) NaClO2 (4) NaClO4
June 2009-44
Given the balanced equation representing a reaction:
Fe2O3 +
2Al--> Al2O3 +
2Fe
During this reaction, the oxidation number of Fe changes
from
(1) +2 to 0 as electrons are transferred
(2) +2 to 0 as protons are transferred
(3) +3 to 0 as electrons are transferred
(4) +3 to 0 as protons are transferred
Jan 2009-44
What is the oxidation number of sulfur in Na2S2O3?
(1) -1 (3) +6
(2) +2 (4) +4
More Practice
|
What is the oxidation number of .
. . |
Highlight to reveal answers |
| 1) N in NO3¯ |
The O is -2 and three of them
makes -6. Since -1 is left over, the N must be
+5 |
| 2) C in CO32¯ |
The O is -2
and three of them makes -6. Since -2 is left
over, the C must be +4 |
| 3) Cr in CrO42¯ |
The O is -2
and four of them makes -8. Since -2 is left
over, the Cr must be +6 |
| 4) Cr in Cr2O72¯ |
The O is -2
and seven of them makes -14. Since -2 is left
over, the two Cr must be +12. Each Cr is
+6. |
| 5) Fe in Fe2O3 |
The O is -2
and three of them makes -6. Each Fe must then be
+3 |
| 6) Pb in PbOH+ |
+2 |
| 7) V in VO2+ |
+5 |
| 8) V in VO2+ |
+4 |
| 9) Mn in MnO4¯ |
+7 |
| 10) Mn in MnO42¯ |
+6 |
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