Determining Oxidation Numbers

 

Oxidation number is the apparent charge of an atom in a compound.

Rules for assigning oxidation numbers.

Follow my order when you assign the numbers and you never can go wrong.

 

1. Free elements are assigned an oxidation state of zero.

ex. Fe, Ag, Br2

2. The Group 1 metals (Li, Na, K, Rb, and Cs) in compounds are always assigned an oxidation state of +1.

ex NaCl  (Na  +1, Cl -1)

3. The Group 2 metals (Be, Mg, Ca, Sr, Ba, and Ra) and also Zn and Cd in compounds are always assigned an oxidation state of +2.

4.Fluorine in compounds is always assigned an oxidation state of -1. (The most electronegative element.)

5.  Hydrogen in compounds is assigned an oxidation state of +1.  

Exceptions Metal hydrides  (you already assigned group 1, so H must be -1)

NaH   (Na +1,  H-1)

6. Oxygen in compounds is assigned an oxidation state of -2.

Exceptions Peroxides  (you already assigned hydrogen +1, so O must be -1)

H2O2  (H +1,  O-1)

With Fluorine (you already assigned fluorine -1, so O must be +2)

OF2 ( O+2, F-1)

7. The sum of the oxidation states of all that atoms in a species must be equal to the net charge on the species.

H2SO4

Since each H is +1 and each O is -2 and the ox. numbers add to zero

2(+1) + S + 4(-2)=0

S is +6

 

8. If all else fails, halogen in compounds is assigned an oxidation state of -1.

More examples

+1 -2

+1 -1

+1 -1

+1 -½

0

+6 -2

N2O

LiH

H2O2

KO2

O2

SO42-

Practice

What is the oxidation number of . . .

Highlight to reveal answers
1) N in NO3¯ The O is -2 and three of them makes -6. Since -1 is left over, the N must be +5
2) C in CO32¯ The O is -2 and three of them makes -6. Since -2 is left over, the C must be +4
3) Cr in CrO42¯ The O is -2 and four of them makes -8. Since -2 is left over, the Cr must be +6
4) Cr in Cr2O72¯ The O is -2 and seven of them makes -14. Since -2 is left over, the two Cr must be +12.  Each Cr is +6.
5) Fe in Fe2O3 The O is -2 and three of them makes -6. Each Fe must then be +3
6) Pb in PbOH+    +2
7) V in VO2+    +5
8) V in VO2+    +4
9) Mn in MnO4¯    +7
10) Mn in MnO42¯    +6