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pH Back to Acid Base Links pH=-log[H+]
Past Regents Problems involving pH
Jan 2004-25
Which of these pH numbers indicates the highest
Aug 2010-9 A solution with a pH of 2.0 has a hydronium ion
concentration ten times greater than a solution with a pH of
Aug 2007-48
What is the pH of a solution that has a hydronium ion concentration
100 times greater than a solution with a pH of 4?
Aug 2006-50
Solution A has a pH of 3 and solution Z has a pH of 6. How many
times greater is the Aug 2003-28. When the pH of a solution changes from a pH of 5 to a pH of 3, the hydronium ion concentration is A. 0.01 of the original content
Jan 2007-48 As the pH of a solution is changed from 3 to 6, the
concentration of hydronium ions Aug 2004-30 Which pH change represents a hundredfold increase in the concentration of H+? 1) pH 5 to pH 7 (3) pH 3 to pH 1
(2) pH 13 to pH 14 (4) pH
4 to pH 3
June 2009-47 Which change in pH represents a hundredfold increase in the
concentration of hydronium ions in a solution?
Aug 2004-48 Which
statement correctly describes a solution with
a pH of 9?
(1) It has a
higher concentration of H3O+ than OH– and
causes litmus to turn blue.
(2) It has a
higher concentration of OH– than H3O+ and
causes litmus to turn blue.
(3) It has a
higher concentration of H3O+ than OH– and
causes methyl orange to turn yellow.
(4) It has a higher concentration of OH– than H3O+ and
causes methyl orange to turn red.
Back to
Acid Base Links
Advanced Chemistry Topics Strong Acids-
Due to the complete dissociation of strong acids in aqueous solution, the
concentration of hydronium ions in the water is equal to the re-duplication of
the acid introduced to solution: [HA] = [H+] = [A−]; pH = −log[H+] Calculate the pH of a 0.100 M solution of HCl. Therefore, the [H+] equals 0.100 M. So, to solve it, you
write:
pH = - log (0.100) = 1.000 Calculate the pH of a 1.00 M solution of HBr. Strong Bases-
Strong bases is pretty much the same as strong acids EXCEPT you'll be
calculating a pOH first, then going to the pH. pH + pOH = 14 Calculate the pH of a 0.100 M solution of NaOH. Therefore, the [OH-] equals 0.100 M. So, to solve it, you
write: pOH = - log (0.100) = 1.000 pH = 14.000 - 1.000 = 13.000 Calculate the pH of a 0.050 M solution of KOH. pH = 14.00 - 1.30 = 12.70
AUTOIONIZATION of WATER --->Auto Ionization of Water
Tutorial<---
notes fromhttp://dbhs.wvusd.k12.ca.us/webdocs/AcidBase/Kw.html H2O(l) + H2O(l)
<==> H3O+(aq) + OH¯(aq) Kw = [H3O+] [OH¯] Kw = water autoionization constant=1.0 x 10-14
@ 25 °C From the chemical equation just above, it can be seen that H3O+
and OH¯ concentrations are in the molar ratio of one-to-one. This means that [H3O+]
= [OH¯]. Therefore the values of [H3O+] and [OH¯]
can be determined by taking the square root of Kw. Hence, both [H3O+]
and [OH¯] equal 1.00 x 10¯7 M in pure water. Result #1: The pH of pure water is 7
By definition, pH = -log [H3O+]
The pH of pure water then equals -log 10¯7, which is 7.
Result #2: If the pH or the pOH is known, the other can be
found.
Take the negative logarithm of each side of the Kw equation as
follows:
- log Kw = -log [H3O+] + -log [OH¯]
-log 1.00 x 10¯14 = -log [H3O+] + -log [OH¯]
Note the use of the add sign on the right side of the equation. The result is
ususally written as:
pKw = pH + pOH = 14
This is an extremely important equation. Learn it well.
Result #3: If the [H3O+] or the [OH¯] is
known, the other can be found.
Simply divide Kw by the known value to get the other.
Suppose [H3O+] is known, then:
[OH¯] = Kw / [H3O+]
Suppose [OH¯] is known, then:
[H3O+] = Kw / [OH¯]
Result #4: If one variable ( [H3O+] or [OH¯] ) changes
value (either up or down), the other variable will change in the opposite
direction.
The change in values will still preserve this fundamental equality:
Kw = [H3O+] [OH¯]
Suppose [H3O+] became larger, therefore the [OH¯]
becomes smaller. |