Questions

Explanations

alkyne

Table Q

(1)   C₂H₄ + H₂O -> CH₃CH₂OH

(2)   C₂H₄ +HCl --> CH₃CH₂Cl

(3)   C₆H₁₂O₆ --> 2CH₃CH₂OH + CO₂

(4)   2CH₃CHO --> C₃H₅CHO + H₂O

3CuCl₂  +  2Al  -->  3 Cu  + 2 AlCl₃

The oxidation number of copper changes from

(1)  +1 to 0

(2)  +2 to 0

(3)  +2 to + 1

(4)  +6 to +3

+2   to   0

each Cl is -1

CH₃COOH + H₂O <=> CH₃COO^-  +  H₃O⁺

According to one acid-base theory, the two H⁺ donors in the equation are:

(1)   CH₃COOH and H₂O

(2)   CH₃COOH and H₃O⁺

(3)   CH₃COO^-   and H₂O

(4)   CH₃COO^-   and H₃O⁺

look are the pairs that are off by 1 H

acids has that extra H

1 on the left of the arrow